2021-04-11:判断二叉树是否是完全二叉树?
2021-04-11:判断二叉树是否是完全二叉树?
福大大 答案2021-04-11:
按层遍历。
代码用golang编写。代码如下:
package main
import (
"container/list"
"fmt"
)
func main() {
head := &TreeNode{Val: 1}
head.Left = &TreeNode{Val: 2}
head.Right = &TreeNode{Val: 3}
head.Left.Left = &TreeNode{Val: 4}
//head.Right.Right = &TreeNode{Val: 5}
ret := isCBT1(head)
fmt.Println(ret)
}
//Definition for a binary tree node.
type TreeNode struct {
Val int
Left *TreeNode
Right *TreeNode
}
func isCBT1(head *TreeNode) bool {
if head == nil {
return true
}
queue := list.New()
// 是否遇到过左右两个孩子不双全的节点
leaf := false
var l *TreeNode
var r *TreeNode
queue.PushBack(head)
for !(queue.Len() == 0) {
head = queue.Remove(queue.Front()).(*TreeNode)
l = head.Left
r = head.Right
if
// 如果遇到了不双全的节点之后,又发现当前节点不是叶节点
(leaf && (l != nil || r != nil)) || (l == nil && r != nil) {
return false
}
if l != nil {
queue.PushBack(l)
}
if r != nil {
queue.PushBack(r)
}
if l == nil || r == nil {
leaf = true
}
}
return true
}
执行结果如下:
***
[左神java代码](https://github.com/algorithmzuo/algorithmbasic2020/blob/master/src/class12/Code01_IsCBT.java)
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