两个二叉树结构与对应节点值是否相同
算法如下:
/*** @description 二叉树结构与对应节点值是否相同* @param {*} xTree 二叉树 x* @param {*} yTree 二叉树 y*/function isEqualTree(xTree, yTree) {const stack = []stack.push(xTree)stack.push(yTree)while (stack.length) {const x = stack.pop(), y = stack.pop()if (!x && !y) continueif (!x || !y) return falseif(x.value != y.value) return falsestack.push(x.right)stack.push(y.right)stack.push(x.left)stack.push(y.left)}return true}
