【c语言】计算两天间的天数
源码
#include<stdio.h>
int total_day(int year,int month,int day)
{
int sum = 0;
switch(month)
{
case 1:sum = day;
break;
case 2:sum = 31 + day;
break;
case 3:sum = 59 + day;
break;
case 4:sum = 90 + day;
break;
case 5:sum = 120 + day;
break;
case 6:sum = 151 + day;
break;
case 7:sum = 181 + day;
break;
case 8:sum = 212 + day;
break;
case 9:sum = 243 + day;
break;
case 10:sum = 273 + day;
break;
case 11:sum = 304 + day;
break;
case 12:sum = 334 + day;
break;
default :
printf("输入的月份有错误\n");
break;
}
if(month >2)
{
if(((year % 4 == 0)&&(year % 100 !=0))||(year % 400) == 0){
sum = sum + 1;
}
}
return sum;
}
int total_year_day(int year1,int year2)
{
int sum_year_day = 0;
int i = 0;
sum_year_day = (year2 - year1) * 365;
for(i=year1 ; i<year2 ; i++)
{
if(((i % 4 == 0)&&(i % 100 !=0))||(i % 400) == 0){
sum_year_day = sum_year_day + 1;
}
}
return sum_year_day;
}
int main()
{
int year1 = 2013, month1 = 1,day1 = 1;
int year2 = 2013, month2 = 1,day2 = 1;
int sum = 0;
printf("请输入起始的年月日(yyyy/mm/dd)");
scanf("%d/%d/%d",&year1,&month1,&day1);
printf("请输入结束的年月日 (yyyy/mm/dd)");
scanf("%d/%d/%d",&year2,&month2,&day2);
sum = total_year_day(year1,year2) - total_day(year1,month1,day1) + total_day(year2,month2,day2);
printf("它们之间相差的天数为:%d\n",sum);
return 0;
}